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// Exa 1.21
clc;
clear;
// Given
// A Volt box design
Vs = 100; // Input voltage (V)
V2 = 5; // Output voltage (V)
Rs = 10*10^6; // Desired sum of resistance(R1+R2) Ohms
// Solution
// By voltage divider formula, we get
// R2/(R1+R2) = V2/Vs ;
// i.e, By simplifying
R2 = Rs*V2/Vs;
R1 = Rs - R2;
printf(' The desired values of R1 and R2 to satisfy Volt box requirements are %.1f M ohms and %.2f M ohms respectively \n ',R1/10^6,R2/10^6);
//The answer provided in the textbook is wrong
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