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///Chapter No 7 Fluid Mechanics
///Example 7.15 Page No:127
/// Find Total energy per unit weight
///Input data
clc;
clear;
S=0.85; //Specific gravity of oil
D=0.08; //Diameter of pipe in m
P=1*10^5; //Intenity of presssure in N/m^2
Z=15; //Total energy bead in m
E=45; //Datum plane in m
Mdw=1*10^3; //Mass density of water constant
g1=9.81; //Gravity constant
rho=S*Mdw; //Mass density of oil
pi1=3.14;
///calculation
rho=S*Mdw; //Mass density of oil
//E=(P/(rho*g1))+((V**2)/(2*g1))+(Z);
V=sqrt((E-((P/(rho*g1))+Z))*(2*g1)); ///Total energy per unit weight in m/s
Q1=(pi1/4)*D^2*V //Discharge in m^3/Kg
///output
printf('mass density of oil=%f Kg/m^3 \n',rho);
printf('Total energy per unit weight= %f m/s \n ',V);
printf('discharge= %f m^3/kg',Q1);
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