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///Example 1.3 Page No:21
///Find Stress in the Steel wire
//Input Data
clc;
clear;
Pt1=600; //Tensils force in N
d1=2*10^-3; //Diameter of steel wire in mm
L1=15; //Length of wire in m
E1=210*10^9; //Modulus of elasticity of the material in GN/M**2
pi1=3.1482;
//Calculation
A1=(pi1/4)*(d1^2); //(1)cross section area
sigmat1=(Pt1)/(A1); //stress in the steel wire
et1=((sigmat1)/(E1)); //(2)Therefore, strain in steel wire is given by
deltaLt1=et1*L1; //(3)Enlongation of the steel wire is given by
pe=((deltaLt1/L1)*100); //(4)Percentage elongation
/////Output
printf('cross section area= %f m^2\n',A1);
printf('stress in the steel wire= %f GN/m^2 \n',sigmat1);
printf('modulus of elasticity=%f \n',et1);
printf('strain in steel wire=%f mm \n',deltaLt1)
printf('percentage elongation=%f percent \n',pe)
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