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/////////Chapter 10 Properties Of Steam
///Example 10.9 Page No:190
////Find Volume of wet steam
//Input data
clc;
clear;
P=12*10^5; //Absolute pressure
//From steam table (pressure basis at 12 bar)
ts=188+273; //In degree celsius
vf=0.001139; //In m**3/Kg
vg=0.1632; //In m**3/Kg
hf=798.4; //In KJ/Kg
hfg=1984.3; //In KJ/Kg
hg=2782.7; //In KJ/Kg
x=0.94;
Cps=2.3;
tsup=350+273; //In degree celsius
//Calcuation
h=hf+x*hfg; //Enthalpy of wet steam in KJ/Kg
v=(1-x)*vf+x*vg; //Volume of wet steam m**3/Kg
u=h-((P*v)/10^3); //Internal Energy in KJ/Kg
hg=2782.7; //Enthalpy of dry & saturated steam in KJ/Kg
v1=vg; //Volume of dry & saturated steam m**3/Kg
u1=hg-((P*vg)/10^3); //Internal Energy in KJ/Kg
h1=hg+Cps*(tsup-ts); //Enthalpy of superheated steam in KJ/Kg
vsup=vg*(tsup/ts); //Volume of superheated steam in m**3/Kg
u2=h1-((P*v)/10**3); //Internal Energy in KJ/Kg
///Output
printf('Enthalpy of wet steam=%f KJ/Kg \n ',h);
printf('Volume of wet steam= %f m^3/Kg \n ',v);
printf('Internal Energy= %f KJ/Kg \n ',u);
printf('Enthalpy of dry & saturated steam=%f KJ/Kg \n',hg);
printf('Volume of dry & saturated steam=%f m^3/Kg \n ',v1);
printf('Internal Energy= %f KJ/Kg \n',u1);
printf('Enthalpy of superheated steam=%f KJ/Kg \n ',h1);
printf('Volume of superheated steam= %f m^3/kg \n',vsup);
printf('Internal Energy= %f KJ/Kg \n ',u2);
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