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/////////Chapter 10 Properties Of Steam
///Example 7.5 Page No:186
///Find Final Enthalpy of the steam
//Input data
clc;
clear;
ti=30; //Temperature in degree celsius
m=2; //Water in Kg
pf=8; //Steam at 8 bar
x=0.9; //Water to dry
tb=30;
///From steam table at 30 degree celsius
hf=125.7;
///h1=hf initial enthalpy of water
///From steam table at 8 bar
ts=170.4; //In degree celsius
hf1=720.9; //In KJ/KG
hfg=2046.6; //In KJ/KG
hg=2767.5; //In KJ/KG
///Calculation
h=hf1+(x*hfg); //Final Enthalpy of the steam in KJ/Kg
Qha=m*(h-hf); //Quantity of the heat in KJ/Kg ///Calculation mistake m is not multiplied by (h-hf) in book
///Output
printf('Final Enthalpy of the steam=%f KJ/Kg \n ',h);
printf('Quantity of the heat=%f KJ/Kg \n',Qha);
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