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/////////Chapter 10 Properties Of Steam
///Example 10.27 Page No:208
//Find Enthalpy of steam
clc;
clear;
//Input data
P1=20; //Initial steam in bar
x1=0.95; //dryness throttled
P2=1.2; //Absolute pressure in bar
//From steam table (pressure basis at 20 bar)
ts=212.4; //In degree celsius
hf=908.6; //In KJ/Kg
hfg=1888.6; //In KJ/Kg
hg=2797.2; //In KJ/Kg
//From steam table (pressure basis at 1.2 bar)
//h2=h1; //In KJ/Kg
ts2=104.8; //In degree celsius
hf2=439.3; //In KJ/Kg
hfg2=2244.1; //In KJ/Kg
hg2=2683.4; //In KJ/Kg
Cps=2.3;
//Calculation
h1=hf+x1*hfg; //Enthalpy of steam in KJ/Kg
tsup2=((h1-hg2)/Cps)+ts2; //Enthalpy of wet steam in degree celsius
DOS=tsup2-ts2; //Degree of superheat in degree celsius
//Output
printf('Enthalpy of steam=%f KJ/Kg \n ',h1);
printf('Enthalpy of wet steam=%f degree celsius \n ',tsup2);
printf('Degree of superheat=%f degree celsius \n',DOS);
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