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/////////Chapter 10 Properties Of Steam
/////Example 10.10 Page No:191
////Find Enthalpy of superheated steam
//Input data
clc;
clear;
P1=10*10^5 //Pressure of steam in bar
tsup1=300+273; //Temperature of steam n degree celsius
P2=1.4*10^5; //Internal energy of steam
x2=0.8; //Dryness fraction
Cps=2.3;
///from steam table properties of saturated steam (temp basis)
///at 25 degree celsius and at 10 bar(pressure basis)
ts1=179.9+273;
vf=0.001127; //In m^3/Kg
vg=0.1943; //In m^3/Kg
hf=762.6; //In KJ/Kg
hfg=2013.6; //In KJ/Kg
hg1=2776.2; //In KJ/Kg
//at 1.4 bar;
ts=109.3; //In degree celsius
vf1=0.001051; //In m^3/Kg
vg1=1.2363; //In m^3/Kg
hf1=458.4; //In KJ/Kg
hfg1=2231.9; //In KJ/Kg
hg=2690.3; //In KJ/Kg
///Calculation
h1=hg1+Cps*(tsup1-ts1); //Enthalpy of superheated steam in KJ/Kg
v1=vg*(tsup1/ts1); //Volume of superheated steam in m**3/Kg
u1=h1-((P1*v1)/10^3); //Internal energy in KJ/Kg
h2=hf1+x2*hfg1; //Enthalpy of wet steam in KJ/Kg
Vwet=(1-x2)*vf1+x2*vg1; //Volume of wet steam in m**3/Kg
u2=h2-((P2*Vwet)/10^3); //Internal energy in KJ/Kg
DeltaU=u1-u2; //Change of Internal energy in KJ/Kg
//Output
printf('Enthalpy of superheated steam= %f KJ/Kg \n ',h1);
printf('Volume of superheated steam=%f m^3/kg \n ',v1);
printf('Internal energy= %f KJ/Kg \n ',u1);
printf('Enthalpy of wet steam= %f KJ/Kg \n ',h2);
printf('Volume of wet steam=%f m^3/kg \n ',Vwet);
printf('Internal energy= %f KJ/Kg \n',u2);
printf('Change of Internal energy= %f KJ/Kg \n ',DeltaU);
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