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//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi
//chapter 5
//example 5.2
//edition 1
//publisher and place:Nelson Engineering
clc;
clear;
l=50; //load in hp
f=60; //frequency in hertz
n=1764; //full load speed in rpm
ns=1800; //synchronous speed of motor in rpm
Pr=.950; //rotational loss in kilowatts
Pcu=1.600; //stator copper loss in kilowatt
Pi=1.200; //iron loss in kilowatt
Pout=l/1.34; //output power at full load is 50 hp in kilowatt
Pd=Pout+Pr; //power developed in kilowatt
s=(ns-n)/ns; //slip of the motor
Pg=Pd/(1-s);
Pin=Pg+Pcu+Pi; //input power in kilowatt
efficiency=Pout/Pin; //motor efficiency
efficiency=efficiency*100;//efficiency in percentage
mprintf("The efficiency of the motor is %d percentage",efficiency)
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