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//Chapter 8, Example 8.1
clc
//Initialisation
vi=10 //input voltage
vo=3 //output voltage
ii=2*10**-3 //input current in ampere
io=5*10**-3 //output current in ampere
//Calculation
av=vo/vi //voltage gain
ai=io/ii //current gain
ap=(vo*io)/(vi*ii) //power gain
//Result
printf("Voltage Gain, Av = %.1f\n",av)
printf("Current Gain, Ai = %.1f\n",ai)
printf("Power Gain, Ap = %.2f\n",ap)
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