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//Chapter 7, Example 7.2
clc
//Initialisation
s=2000 //apparent power
p=0.75 //power factor
v=240 //voltage
//Calculation
ap=s*p //active power
phi=sqrt(1-(p**2)) //phase angle in radians
q=s*phi //reactive power in var
i=s/v //current in ampere
//Results
printf("(a) Apparent Power, S = %d VA\n",s)
printf("(b) Active Power, P = %d W\n",ap)
printf("(c) Reactive Power, Q = %d var\n",q)
printf("(d) Current, I = %.2f A\n",i)
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