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//Chapter 7, Example 7.1
clc
//Initialisation'
v=50 //voltage
i=5 //current
phi=30 //angle in degree
pi=3.14 //pi
//Calculation
s=v*i //apparent power
p=cos(phi*3.14/180) //power factor
ap=s*p //active power
//Results
printf("(a) Apparent Power, S = %d VA\n",s)
printf("(b) Power Factor = %.3f Degree\n",p) //wrong answer in textbook
printf("(c) Active Power, P = %.1f W\n",ap) //wrong answer in textbook
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