3809/CH5/EX5.6/EX5_6.sce


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//Chapter 5, Example 5.6

clc
//Initialisation'
L=10**-2                   //inductance
I=5                         //current in ampere


//Calculation
e=(1/2)*L*I**2               //stored energy

//Results
printf("Stored Energy = %d mJ",e*10**3)