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//Chapter 5, Example 5.5
clc
//Initialisation'
L1=10 //inductance
L2=20 //inductance
//Calculation
Ls=L1+L2 //inductance in series
Lp=(L1*L2)/(L1+L2) //inductance in parallel
//Results
printf("(a) Inductance in Series Ls = %d H\n",Ls)
printf("(b) Inductance in Parallel Lp = %.2f H\n",Lp)
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