3809/CH3/EX3.1/EX3_1.sce


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//Chapter 3, Example 3.1

clc
//Initialisation'
i1=8                       //current in amp
i2=1                       //current in amp
i3=4                       //current in amp

//Calculation
i4=i3+i2-i1                       //current in amp


//Results
printf("Current, I4 = %d A",i4)