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//Chapter 2, Example 2.4
clc
//Initialisation
v1=5 //voltage
v2=5 //voltage
r=10 //resistance in ohm
//Calculation
p1=v1^2/r //Power in watt when a constant 5 V applied
p2=v2^2/r //Power in watt when a sine wave of 5 V r.m.s is applied
p3=((v1^2)/2)/r //Power in watt when a sine wave of 5 V peak is applied
//Result
printf("(a) P = %.1f W\n",p1)
printf("(b) Pav = %.1f W\n",p2)
printf("(c) Pav = %.2f W\n",p3)
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