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//Chapter 18, Example 18.11
clc
//Initialisation
VCC=10 //voltage
R2=3*10**3 //resistance in ohm
R1=7*10**3 //resistance in ohm
RE=10**3 //resistance in ohm
RC=3*10**3 //resistance in ohm
VBE=0.7 //base emitter voltage
av=1 //small sg voltage gain
RE2=2*10**3 //resistance in ohm
RC2=4*10**3 //resistance in ohm
//Calculation
VB=VCC*(R2/(R1+R2)) //Quiescent base voltage
VE=VB-VBE //Quiescent emitter voltage
IE=VE/RE //Quiescent emitter current
VC1=VCC-(IE*RC) //Quiescent collector voltage
VB2=VC1 //bias voltage
VE2=VB2-VBE //emitter voltage
IC2=VE2/RE2 //collector current in ampere
VC2=VCC-(IC2*RC2) //collector voltage
Av=(-RC/RE)*(-RC2/RE2) //overall gain
//Results
printf("Quiescent output voltage = %.1f V\n",VC2)
printf("Overall Voltage Gain = %d",Av)
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