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//Chapter 17, Example 17.4
clc
//Initialisation
VDD=15 //voltage
Vq=10 //quiescent output voltage
RD=2.5*10**3 //resistance in Ohm
Vp=-6 //voltage
IDSS=8*10**-3 //saturation drain current in amp
//Calculation
VR=VDD-Vq //voltage
ID=VR/RD //quiescent drain current
VGS=Vp*(1-sqrt(ID/IDSS)) //voltage
Rs=VGS/ID //resistance in ohm
//Results
printf("Rs = %.1f kOhm\n",-Rs/1000)
printf("ID = %d mA\n",ID*1000)
printf("VGS = %d V\n",VGS)
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