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//Book Name:Fundamentals of Electrical Engineering
//Author:Rajendra Prasad
//Publisher: PHI Learning Private Limited
//Edition:Third ,2014
//Ex7_5.sce.
clc;
clear;
P=500e3; //KVA rating of the transformer
Vp=6600; //primary voltage in V
Vs=440; //secondary voltage in V
rp=0.45; //primary winding resistance in ohms
rs=0.0015; //secondary winding resistance in ohms
iron_loss=2.9e3;
pf=0.8; //power factor lagging
//case1
printf("\n (a)")
Ip=P/Vp; //primary current in A
Is=P/Vs; //secondary current in A
Ip_square_rp=Ip^(2)*rp; //primary copper loss
Is_square_rs=Is^(2)*rs; //secondary copper loss
FL_copper_loss=Ip_square_rp+Is_square_rs; //FL means "full load"
FL_total_loss=iron_loss+FL_copper_loss;
FL_output_power=P*pf;
FL_input_power=FL_output_power+FL_total_loss;
FL_efficiency=(FL_output_power/FL_input_power)*100;
printf("\n Full load efficiency=%2.2f percentage \n",FL_efficiency)
//case2
printf("\n (b)")
HL_copper_loss=FL_copper_loss*(0.5^2); //HL means "half load"
HL_total_loss=iron_loss+HL_copper_loss;
HL_output_power=FL_output_power/2;
HL_input_power=HL_output_power+HL_total_loss;
HL_efficiency=(HL_output_power/HL_input_power)*100;
printf("\n Half load efficiency=%2.4f percentage \n",HL_efficiency)
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