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clear
//Given
mass = 5 //Kg
frequency = 10 //Hz
stress_allow = 200 //MPa
R = 0.5 //m
//caliculations
//
w = 2*%pi*frequency //rad/sec
a = (w**2)*R //sq.m/sec
F = mass*a //N
A_req = F/stress_allow //sq.m , The required area for aloowing stress
printf("\n The required size of rod is: %0.2f sq.m",A_req)
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