blob: 239803ffde7c32e3f4d79507cf5aff6df3be45be (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
|
// Problem 8.4,Page no.209
clc;clear;
close;
G=80 //GPa //Modulus of rigidity
P=1 //KN //Load
dell=10 //cm //Deflection
sigma_s=350 //MPa //Max shear stress
rho=78000 //N/m**3 //Density of materials
//Calculations
U=P*1000*dell*10**-2*2**-1 //N*m //Energy stored
//Again U=sigma_s**2*V*(4*G)**-1
//After substituting values in above equation and further simplifying we get
V=50*4*80*10**9*((350*10**6)**2)**-1 //m**3 //Volume
W=V*rho //N //Weight
//Now T=P*R=%pi*d**3*sigma_s*16**-1
//After substituting values in above equation and further simplifying
D=(10**6*16*(2*%pi*350*10**6)**-1)**0.5*10**2 //cm //Mean diameter of coil
k=P*10**3*(dell*10**-2)**-1 //stiffness
//Also k=D*n**-1*10**6
//After substituting values in above equation and further simplifying
n=10**6*D*10**-2*k**-1 //number of turns
//Result
printf("The Value of weight is %.3f N",W)
printf("\n Mean coil diameter is %.2f",D);printf(" cm")
printf("\n The number of Turns is %.d",ceil(n))
|