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// Problem 3.2,Page no.54
clc;clear;
close;
//D=(D_0-2) //cm //Inside Diameter of cyclinder
//A=(%pi*(D_0-1)) //cm**2 //Area of cross-section
//L=(%pi*(D_0-1)*5400) //N //Crushing load for column
F=6 //Factor of safety
T=1 //cm //wall thickness of cyclinder
//S=L*F**-1
//After Simplifying,we get
S=600*10**3
//Calculations
D_0=(S*F)*(%pi*54000)**-1+1 //cm //Outside diameter of cyclinder
//Result
printf("The outside Diameter of cyclinder is %.2f cm",D_0)
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