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// Problem no 14.8,Page No.334
clc;clear;
close;
H=10 //m //height of dam
a=1 //m //top width
b=7 //m //Bottom width
rho_mason=19620 //N/m**3 //weight of mason
rho_w=9810 //N/m**3 //density of water
//Calculations
//Lateral thrust
P=rho_w*H**2*2**-1
//weight of dam
W=(rho_w*H*2**-1*a)+(rho_mason*(a+b)*2**-1*H)
//Taking Moment at B,M_B=0
x_bar=((rho_w*H*2**-1*1*3**-1)+(rho_mason*H*2**-1*2*3**-1)+(rho_mason*H*1.5)+(rho_mason*H*5*11*2**-1*3**-1))*W**-1
//Now using relation we get
x=P*W**-1*H*3**-1
//Eccentricity
e=x_bar+x-b*2**-1
//Max stress
sigma_max=W*b**-1*(1+6*e*b**-1)
//Min stress
sigma_min=W*b**-1*(1-6*e*b**-1)
//Result
printf("The Max stresses on the base is %.2f",sigma_max);printf(" N/m**2")
printf("\n The Min stresses on the base is %.2f",sigma_min);printf(" N/m**2")
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