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// Problem no 10.7,Page No.261
clc;
clear;
close;
//Calculations
theta=atan(1*2**-1)*(180*%pi**-1) //Radian
//Taking moment about A
R_EH=10*8*4**-1
//Horizontal component of reaction at A
R_AH=20 //KN
//Applying the summation of horizontal forces we get
F_AB=20*cos(theta*%pi*180**-1)**-1
//Applying the summation of vertical forces we get
R_AV=10*5**0.5*sin(theta*%pi*180**-1)
//Vertical Reaction at E
R_EV=0
//Joint C
//Applying the summation of vertical forces we get
F_DC=10*sin(theta*%pi*180**-1)**-1
//Applying the summation of horizontal forces we get
F_CB=F_DC*cos(theta*%pi*180**-1)
//Joint D
//Applying the summation of vertical forces we get
F_DB=F_DC*sin(theta*%pi*180**-1)
//Applying the summation of horizontal forces we get
F_DE=F_DC*cos(theta*%pi*180**-1)
//Joint E
//Applying the summation of vertical forces we get
F_EB=R_EV*sin(theta*%pi*180**-1)
//Result
printf("Forces in Each members are as follows:F_AB %.2f",F_AB);printf(" KN(Tensile)")
printf("\n :F_DC %.2f",F_DC);printf(" KN(compression)")
printf("\n :F_CB %.2f",F_CB);printf(" KN(Tensile)")
printf("\n :F_DB %.2f",F_DB);printf(" KN(Tensile)")
printf("\n :F_DE %.2f",F_DE);printf(" KN(compression)")
printf("\n :F_EB %.2f",F_EB);printf(" KN")
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