377/CH9/EX9.7/9_7.sce


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disp("Va=(K*T/q)*log((J/Js)+1)");
a=0.0259;  //say 
J=10^5;
Js=250*10^-3;
Va=a*log((J/Js)+1);
printf('\n The value of Va is %fV',Va);