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Na=3*10^16;
Nd=8*10^15;
ni=10^10;
a=0.025852; //say a=K*T/q
disp("Vbi=a*log(Na*Nd/ni^2);");
Vbi=a*log(Na*Nd/ni^2);
printf('\n The value of built-in-potential is %1.3fV',Vbi);
disp("Xn=sqrt((2*Єs*Vbi*Na)/(q*Nd*(Na+Nd)))");
q=1.6*10^-19;
b=11.7*8.85*10^-14;
Xn=sqrt((2*b*Vbi*Na)/(q*Nd*(Na+Nd)));
printf('\n The value of depletion width is %f*10^-5 cm',Xn*10^5);
Neff=Na*Nd/(Na+Nd);
printf('\n The value of Neff is %f*10^15',Neff*10^-15);
c=11.7*8.85;
q1=1.6;
Cj0=sqrt(c*q1*Neff/(2*Vbi))/3;
printf('\n The value of Cj0 is %f*10^-8 F/cm^2',Cj0*10^-8);
Va=-3;
Cj3=Cj0*10^-8*sqrt(Vbi/(Vbi-Va));
printf('\n The value of Cj(-3) is %f*10^-8 F/cm^2',Cj3);
W=sqrt(2*b*(Vbi-Va)/(q*Neff));
printf('\n The value of total depletion width is %f*10^-5 cm',W*10^5);
Emax=2*(Vbi-Va)/W;
printf('\n The value of maximum electric field is %f V/cm',Emax);
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