377/CH8/EX8.2/8_2.sce


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disp("μd=-Rh*σ");
Rh=-0.55*10^-10;
a=5.9*10^7;  //say σ=a
b=-Rh*a;  //say μd=b
printf('\n The value of μd is %f*10^-3 m^2/V/s',b*10^3);