377/CH4/EX4.10/4_10.sce


1
2
3
4
5
6

disp("∆Ed=13.64*(me/mo)*(1/(Єr^2)) eV");
disp("me = (0.015)*m0");
a=0.015;
c=18;  //say Єr=c
d=13.64*(a)*(1/(c^2));
printf('the value of the ∆Ed = %f eV',d);