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clear
//Given
m=1
c=1
a=100 //W
b=15
t=7.5 //second
P=1 //KW
C=860 //Kcal
//Calculation
A=m*c*(a-b)
B=P*t/60.0
D=B*C
n=A*a/D
//Result
printf("\n Efficiency of the kettle is %0.1f percentage",n)
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