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clear
//Given
a=10
b=5.0
c=9.0
d=19.0
//Calculation
I2=(a-c)/((b*a)-(d*c))
I1=(1-(5*I2))/c
I=I1+I2
pd=I*10
//Result
printf("\n Current through each cell is %0.2f A",I)
printf("\n Potential difference across 10 ohm wire is %0.3f V",pd)
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