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clear
//Given
R2=50.0 //ohm
R3=50.0 //ohm
R4=75.0 //ohm
E=4.75
R1=100
//Calculation
Rbc=1/((1/R2)+(1/R3)+(1/R4))
R=R1+Rbc
I=E/R
R11=I*R1
Vbc=E-(I*R1)
I2=Vbc/R2
I3=Vbc/R3
I4=Vbc/R4
//Result
printf("\n Equivalent resistance of the circuit is %0.3f ohm", R)
printf("\n Current in R2 is %0.3f A",I2)
printf("\n Current in R3 is %0.3f A",I3)
printf("\n Current in R4 is %0.3f A",I4)
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