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clear
//Given
R1=2.0 //ohm
R2=3 //ohm
R3=2.8
E=6 //V
//Calculation
Rab=R1*R2/(R1+R2)
Rt=Rab+R3
I=E/Rt
Vab=I*Rab
I1=Vab/2.0
//Result
printf("\n The steady state current is %0.3f A", I1)
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