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clear
//Given
Rab=500.0 //ohm
Rl=500 //ohm
Rbc=1500 //ohm
E=50 //Volts
Rac=2000.0 //ohm
V=40
//Calculation
R=Rbc*Rl/(Rbc+Rl)
I=E/(Rab+R)
Pd=I*Rab
Rl1=E-Pd
I1=E/Rac
R12=V/I1
//Result
printf("\n (i) Potential difference across the road is %0.2f V",Rl1)
printf("\n (ii) Resistance at BC is %0.3f ohm", R12)
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