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clear
//Given
R1=5 //ohm
R2=9 //ohm
R3=14 //ohm
R4=11
R5=7
R6=18
R7=13
R8=22
V=22
//Calculation
Rec=(R1+R2)*R3/(R1+R2+R3)
Rbe=(R4+R5)*R6/(R4+R5+R6)
Rae=(R7+R2)*R8/(R7+R2+R8)
I=V/Rae
//Result
printf("\n The value of current in the branch AF is %0.3f A", I)
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