3769/CH5/EX5.16/Ex5_16.sce


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clear
//Given
ne=2.8*10**18
np=1.2*10**18
e=1.6*10**-19
t=1                             //S
V=220

//Calculation
q=(ne+np)*e
I=q/t
R=V/I

//Result
printf("\n Effective resistance of the tube is  %0.0f  ohm",R)