3769/CH4/EX4.11/Ex4_11.sce


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clear
//Given
c1=0.5                  //micro F
c2=0.3                  //micro F
c3=0.2                  //micro F

//Calculation
Cp=c1+c2+c3   
Cs=(1/c1)+(1/c2)+(1/c3)

//Result
printf("\n  The ratio ofmaximum capacitance to minimum capacitance is  %0.1f  ",Cs)