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clear
//Given
Vbb=2.0 //v
Rc=2000 //ohm
B=100
Vbe=0.6 //V
//Calculation
Ic=Vbb/Rc*10**3
Ib=Ic/B
Ib1=10*Ib
Rb=(Vbb-Vbe)/Ib
Ic=B*Ib1
//Result
printf("\n d.c. collector current is %0.3f mA",Ic)
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