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clear
//Given
N=3.67*10**10 //dis/second
r=226.0
A=6.023*10**23
//Calculation
n=A/r
l=N/n
D=0.693/l
a=D/(3600.0*24.0*365.0)
//Result
printf("\n Half life of radium is %0.0f years",a)
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