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clear
//Given
t=5000 //Days
t1=2000.0
a=0.693
//Calculation
//
dt=(a*t)/t1
N=log10(dt)
l=a*N/(t1)
//Result
printf("\n (i) The fraction remaining after 5000 days is %0.3f ",N)
printf("\n (ii) The activity of sample after 5000 days is %0.1f *10**8 Bq",l*10**5)
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