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clear
//Given
v=2.1*10**7 //m/s
a=4.8*10**7 //C/Kg
Z=79
e=1.6*10**-19
m=9*10**9
//Calculation
r0=(2*m*Z*e*a)/v**2
//Result
printf("\n Distance of the closest approach is %0.1f *10**-14 m",r0*10**14)
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