3769/CH24/EX24.1/Ex24_1.sce


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clear
//Given
k=7.68*10**6*1.6*10**-19                   //J
e=1.6*10**-19
Z=29
m=9*10**9

//Calculation
r=(m*2*Z*e**2)/k

//Result
printf("\n The distance of the closest approach is %0.1f *10**-14 m",r*10**14)