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clear
//Given
u=-60.0 //cm
R=25.0 //cm
y1=1
y2=1.5
//Calcution
v=1/((((y2-y1)/R)+(y1/u))/y2)
P=(y2-y1)/(R*10**-2)
//Result
printf("\n Position of the image is %0.3f cm", v)
printf("\n Power of the refracting surface is %0.3f dioptre", P)
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