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clear
//Given
V=200 //V
Vp=200 //V
n=200.0
Ip=2 //A
//Calculation
Vs=Vp*n
Is=(Ip*V)/Vs
//Result
printf("\n (i) Voltage developed in the secondary is %0.3f V", Vs)
printf("\n (ii) The current in the secondary is %0.3f A",Is )
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