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clear
//Given
f=50 //Hz
L=0.03
R=8 //ohm
Ev=240 //V
//Calculation
//
Xl=2*%pi*f*L
Z=sqrt(R**2+Xl**2)
Iv=Ev/Z
P=Iv**2*R
a=R/Z
Xc=2*Xl
C=1/(2*%pi*f*Xc)
//Result
printf("\n (i) The value of current is %0.2f A",Iv)
printf("\n The value of power is %0.0f W",P)
printf("\n Power factor is %0.2f lag",a)
printf("\n (ii) The vaue of capacitance is %0.0f micro F",C*10**6)
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