3769/CH12/EX12.9/Ex12_9.sce


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clear
//Given
g=9.8
h=10
B=1.7*10**-5
l=1               //m

//Calculation
//
v=sqrt(2*g*h)
e=B*l*v

//Result
printf("\n Potential difference between its end is %0.3f  *10**4 V", e*10**4)