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clear
//Given
L=130*10**-3 //H
I1=20 //mA
I2=28 //mA
t=140.0*10**-3 //S
//Calculation
l=I2-I1
e=(-L*l)/t
//Result
printf("\n Magnitude of induced e.m.f is %0.2f *10**-3 V",e)
printf("\n Direction oppose the increase in current")
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