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clc
//
//Variable declaration
sY=40 // Stress(ksi)
sU=60 // Stress(ksi)
E=(10.6)*((10**6)) // Modulus of rigidity(psi)
FS=3 // Factor of safety
//Calculation
//Moment of Inertia
E=(10.6)*((10**6)) // Modulus of rigidity(psi)
I=(((1/12.0)*3.25*(5**3))-((1/12)*(2.75)*(4.5**3))**2) // Centroidal moment of inertia of a rectangle
//Allowable Stress
sALL=(sU/FS) // Allowable stress(ksi)
//Case(a) Bending Moment
c=(1/2.0)*(5) // Radius(in)
M=((12.97)*(20))/2.5 // Bending moment(kip.in)
//Case(b) Radius of Curvature
p=((10.6*(10**6)*12.97)/(103.8*(10**3))**1) // Radius of curvature(in)
p=((p*0.08333)) // Converting into feet(ft)
//Alternative Solution.
Em=(sALL/(E*((10**-3))*(1.0))) // Maximum strain(in./in)
p=(c/Em) // Radius of curvature(in)
p=((p*0.08333)) // Converting into feet(ft)
// Result
printf("\n Bending moment M for which factor of safety is 3 = %0.3f kip.in' ,M)
printf("\n Radius of curvature of tube = %0.3f ft' ,p)
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