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//Fluid Systems- By Shiv Kumar
//Chapter 7- Performance of Water Turbine
//Example 7.13
// To Determine the maximum flow rate and specific speed for the Turbine and To Find Speed, Power Output and Water Consumption of the Model.
clc
clear
//Given:-
Lr=10; //Scale Ratio
DpbyDm=Lr;
DmbyDp=1/DpbyDm;
//For Prototype
Pp=1000; //Power , kW
Hp=14; //Head, m
Np=130; //Speed, rpm
eta_o=91/100; //Overall efficiency
//For Model
Hm=6; //Head, m
//Data Required:-
rho=1000; //Density of Water, Kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Qp=Pp*1000/(rho*g*Hp *eta_o ); //m^3/s
Ns=Np*Pp^(1/2)/(Hp^(5/4)); //Specific Speed, In SI UNITS
Nm=Np*DpbyDm*(Hm/Hp)^(1/2); //rpm
Qm=Qp*(Nm/Np)*(DmbyDp)^3; //m^3/s
Pm=Pp*(Nm/Np)^3*DmbyDp^5; //KW
//Results:-
printf("For the Turbine : \n\t")
printf("Maximum Flow Rate, Qp=%.f m^3/s\n\t",Qp)
printf("Specific Speed, Ns=%.2f (SI Units)\n\n",Ns)
printf("For the Model : \n\t")
printf("Speed, Nm=%.2f rpm\n Power Output, Pm=%.2f kW\n Water Consumption, Qm=%.4f m^3/s \n", Nm,Pm,Qm) //The Answer vary due to Round off Error
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