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//Fluid System By Shiv Kumar
//Chapter 6 - Kaplan and Propeller Turbines
//Example 6.1
//To Find (a)Discharge (b)Diameter of Hub And Diameter of Runner (c)Speed
clc
clear
//Given:
P=37; //Shaft Power, MW
H=22; //Head, m
eta_0=92/100; //Overall Efficiency
dbyD=1/3; //Ratio of Diameters of Hub and Runner
Kf=0.6; //Flow Ratio
Ku=2; //Speed Ratio
//Data Required:
rho=1000; //Density of Water, Kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations
//(a)Discharge, Q
Q=P*10^6/(rho*g*H*eta_0); //m^3/s
//(b)Diameter of Hub(d) And Diameter of Runner(D)
d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*(dbyD^-2-1))); //m
D=d/dbyD; //m
//(c) Speed,N
N=Ku*60*sqrt(2*g*H)/(%pi*D); // rpm
//Results
printf("(a)Discharge, Q=%.2f m^3/s \n",Q) //The answer vary due to round off error
printf(" (b)Diameter of Hub, d=%.2f m \n",d)
printf(" Diameter of Runner, D=%.2f m \n",D) //The answer vary due to round off error
printf(" (c)Speed, N=%.2f rpm \n",N) //The answer vary due to round off error
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