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//Fluid Systems - By Shiv Kumar
//Chapter 5- Francis Turbine
//Example 5.6
//To Find (a) Guide Blade Angles (b) Blade Angle at Inlet (c) Power Developed
clc
clear
//Given Data:-
Q=300; //Discharge, litres/s
Di=0.36; //Diameter of Runner at Outlet, m
Dp=Di; //Diameter of Outlet Pipe, m
H=36; //Head, m
ui=21; // Velocity of Wheel at Inlet, m/s
//Data Required:-
rho=1000; //Density of water, Kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Vfo=(Q/1000)/((%pi/4)*Di^2); //m/s
Vo=Vfo;
Vfi=Vfo;
//By Energy Balance Equation,
Vwi=(g*H-Vo^2/2)/ui; //m/s
// (a) Guide Blade Angles, alpha_i, alpha_o
alpha_i=atand(Vfi/Vwi); //degrees
//As Discharge is Radial,
alpha_o=90; //degrees
// (b) Blade Angle at Inlet, beta_i
beta_i=180-atand(Vfi/(ui-Vwi)); //degrees
// (c) Power Developed by Runner
P=rho*(Q/1000)*Vwi*ui/1000; //kW
//Results:-
printf(" (a) Guide Blade Angles are: \n alpha_i=%.2f Degrees, alpha_o=%.f Degrees\n",alpha_i, alpha_o )
printf(" (b) Blade Angle at Inlet, beta_i=%.2f Degrees\n",beta_i)
printf(" (c) Power Developed by Runner, P =%.2f kW\n",P) //The Answer Vary due to Round off Error
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