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//Fluid system - By - Shiv Kumar
//Chapter 4 - Pelton Turbine (Impulse Turbine)
//Example 4.9
clc
clear
//Given Data:-
P=3000; //Power developed, kW
H=300; //Head, m
N=375; //Speed, rpm
eta_O=83/100; //Overall efficiency
Ku=0.46; //Speed ratio
Cv=0.98; //Co-efficient of Velocity
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
//(i) Diameter of Turbine, D
D=60*Ku*sqrt(2*g*H)/(%pi*N); //m
//(ii) Diameter of Jet, d
Q=P*1000/(rho*g*H*eta_O); //m^3/s
Vi=Cv*sqrt(2*g*H); //m/s
d=(Q/((%pi/4)*Vi))^(1/2); //m
//Results:-
printf("(i) Diameter of the Turbine, D=%.2f m \n", D) //The answer vary due to round off error
printf("(ii) Diameter of the Jet, d=%.4f m", d) //The answer vary due to round off error
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